Write a program that lets you know if you can have a key or not, based on your role at the school.
First ask for the user’s role at the school. They can be a student, administrator, or a teacher. (And remember that capitalization is important! ‘Student’ is not the same as ‘student’.)
Example 1: Administrator or Teacher
For example, if this was the input:
Are you an administrator, teacher, or student?: teacher
This should be the output:
Administrators and teachers get keys!
Example 2: Student
And if this was the input:
Are you an administrator, teacher, or student?: student
This should be the output:
Students do not get keys!
(Note: You should also be able to handle a situation where the user enters a value other than administrator, teacher or student and tell them they must be one of the three choices!)
Example 3: Other
If they input anything else:
Are you an administrator, teacher, or student?: secretary
This should be the output:
You can only be an administrator, teacher, or student!
В первом задании пропустил srand(time(NULL)); допишешь его.
1)
typedef size_t uint32;
mt19937 gen{ random_device()() };
uniform_int_distribution<uint32> uid(20, 100);
const uint32 N = 10;
int main()
{
uint32 arr[N], pos{0}, neg{0};
for (uint32 i = 0; i < N; ++i) {
arr[i] = uid(gen);
cout << arr[i] << » «;
if (arr[i] % 2 == 0) ++pos;
else ++neg;
}
cout << endl << pos << «/» << neg << endl;
system(«pause»);
}
2)
typedef size_t uint32;
mt19937 gen{ random_device()() };
uniform_int_distribution<uint32> uid(0, 100);
const uint32 N = 10;
int main()
{
uint32 arr[N], lf{ 0 }, hf{ 0 }, sum1{ 0 }, sum2{ 0 };
for (uint32 i = 0; i < N; ++i) {
arr[i] = uid(gen);
cout << arr[i] << » «;
if (arr[i] >= 50) {
++lf;
sum1 += arr[i];
} else {
++hf;
sum2 += arr[i];
}
}
cout << endl << sum1 / lf << «/» << sum2 / hf << endl;
system(«pause»);
}