Прошу решите пожалуйста,формулой корней квадратного уравнения.​

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125
1. х² + 5х – 14 = 0
а = 1, b = 5, c = -14
D = b² – 4ac = 5² – 4•(–14)•1 = 25 + 56 = 81 = 9²

2. х² – 14х + 40 = 0
a = 1, b = -14, c = 40
D = (-14)² — 4•40•1 = 196 – 160 = 36 = 6²

3. 3у² — 13у + 4 = 0
a = 3, b = -13, c = 4
D = (-13)² — 4•3•4 = 169 – 48 = 121 = 11²

4. 12m² + m — 6 = 0
a = 12, b = 1, c = -6
D = 1² — 4•12•(-6) = 1 + 288 = 289 = 17²

5. x² + 6x — 2 = 0
a = 1, b = 6, c = -2
D = 6² – 4•1•(-2) = 36 + 8 = 44 = √44

6. 3x² — 4x — 5 = 0
a = 3, b = -4, c = -5
D = (-4)² – 4•3•(-5) = 16 + 60 = 76 = √76

7. 25x² + 60x + 36 = 0
a = 25, b = 60, c = 36
D = 60² – 4•25•36 = 3600 – 3600 = 0

8. x² — 8x + 18 = 0
a = 1, b = -8, c = 18
D = (-8)² – 4•18•1 = 64 — 72 = -8
Нет корней

126
1. (4х + 1)(х — 3) = 12
4х² — 12х + х — 3 = 12
4х² — 11х — 15 = 0
a = 4, b = -11, c = -15
D = (-11)² – 4•4•(-15) = 121 + 240 = 361 = 19

2. (x + 2)(x — 3) – (2x — 5)(x+3) = x(x-5)
x² — 3x + 2x — 6 – 2x² — 6x + 5x + 15 – x² + 5x = 0
–2x² + 3x + 9 = 0
a = -2, b = 3, c = 9
D = 3² – 4•9•(-2) = 9 + 72 = 81 = 9²

3. (6x — 5)² + (3x — 2)(3x + 2) = 36
((6x)² — 2•6x•5 + 5²) + (9x² — 4) = 36
36x² – 60x + 25 + 9x ² – 4 – 36 = 0

3x² – 4x = 0
x (3x – 4) = 0
x = 0 или 3х – 4 = 0